Optimal. Leaf size=170 \[ -\frac{\left (d^2-e^2 x^2\right )^{3/2} \left (A e^2-B d e+C d^2\right )}{d e^3 (d+e x)^2}-\frac{\sqrt{d^2-e^2 x^2} \left (5 C d^2-2 e (2 B d-A e)\right )}{2 d e^3}-\frac{\tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right ) \left (5 C d^2-2 e (2 B d-A e)\right )}{2 e^3}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)} \]
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Rubi [A] time = 0.202595, antiderivative size = 170, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 34, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.147, Rules used = {1639, 793, 665, 217, 203} \[ -\frac{\left (d^2-e^2 x^2\right )^{3/2} \left (A e^2-B d e+C d^2\right )}{d e^3 (d+e x)^2}-\frac{\sqrt{d^2-e^2 x^2} \left (5 C d^2-2 e (2 B d-A e)\right )}{2 d e^3}-\frac{\tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right ) \left (5 C d^2-2 e (2 B d-A e)\right )}{2 e^3}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)} \]
Antiderivative was successfully verified.
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Rule 1639
Rule 793
Rule 665
Rule 217
Rule 203
Rubi steps
\begin{align*} \int \frac{\left (A+B x+C x^2\right ) \sqrt{d^2-e^2 x^2}}{(d+e x)^2} \, dx &=-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)}-\frac{\int \frac{\left (e^2 \left (C d^2-2 A e^2\right )+e^3 (3 C d-2 B e) x\right ) \sqrt{d^2-e^2 x^2}}{(d+e x)^2} \, dx}{2 e^4}\\ &=-\frac{\left (C d^2-B d e+A e^2\right ) \left (d^2-e^2 x^2\right )^{3/2}}{d e^3 (d+e x)^2}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)}-\frac{\left (-3 e^5 \left (C d^2-2 A e^2\right )-2 \left (-d e^5 (3 C d-2 B e)-e^5 \left (C d^2-2 A e^2\right )\right )\right ) \int \frac{\sqrt{d^2-e^2 x^2}}{d+e x} \, dx}{2 d e^7}\\ &=-\frac{\left (5 C d^2-2 e (2 B d-A e)\right ) \sqrt{d^2-e^2 x^2}}{2 d e^3}-\frac{\left (C d^2-B d e+A e^2\right ) \left (d^2-e^2 x^2\right )^{3/2}}{d e^3 (d+e x)^2}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)}-\frac{\left (-3 e^5 \left (C d^2-2 A e^2\right )-2 \left (-d e^5 (3 C d-2 B e)-e^5 \left (C d^2-2 A e^2\right )\right )\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx}{2 e^7}\\ &=-\frac{\left (5 C d^2-2 e (2 B d-A e)\right ) \sqrt{d^2-e^2 x^2}}{2 d e^3}-\frac{\left (C d^2-B d e+A e^2\right ) \left (d^2-e^2 x^2\right )^{3/2}}{d e^3 (d+e x)^2}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)}-\frac{\left (-3 e^5 \left (C d^2-2 A e^2\right )-2 \left (-d e^5 (3 C d-2 B e)-e^5 \left (C d^2-2 A e^2\right )\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )}{2 e^7}\\ &=-\frac{\left (5 C d^2-2 e (2 B d-A e)\right ) \sqrt{d^2-e^2 x^2}}{2 d e^3}-\frac{\left (C d^2-B d e+A e^2\right ) \left (d^2-e^2 x^2\right )^{3/2}}{d e^3 (d+e x)^2}-\frac{C \left (d^2-e^2 x^2\right )^{3/2}}{2 e^3 (d+e x)}-\frac{\left (5 C d^2-2 e (2 B d-A e)\right ) \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{2 e^3}\\ \end{align*}
Mathematica [A] time = 0.242847, size = 109, normalized size = 0.64 \[ \frac{\frac{\sqrt{d^2-e^2 x^2} \left (2 e (-2 A e+3 B d+B e x)+C \left (-8 d^2-3 d e x+e^2 x^2\right )\right )}{d+e x}-\tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right ) \left (2 e (A e-2 B d)+5 C d^2\right )}{2 e^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.06, size = 439, normalized size = 2.6 \begin{align*}{\frac{Cx}{2\,{e}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}+{\frac{C{d}^{2}}{2\,{e}^{2}}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}+2\,{\frac{B}{{e}^{2}}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}-3\,{\frac{dC}{{e}^{3}}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}+2\,{\frac{Bd}{e\sqrt{{e}^{2}}}\arctan \left ({\sqrt{{e}^{2}}x{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ) }-3\,{\frac{C{d}^{2}}{{e}^{2}\sqrt{{e}^{2}}}\arctan \left ({\sqrt{{e}^{2}}x{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ) }-{\frac{A}{d{e}^{3}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-2}}+{\frac{B}{{e}^{4}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-2}}-{\frac{dC}{{e}^{5}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-2}}-{\frac{A}{de}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}-{A\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.88055, size = 409, normalized size = 2.41 \begin{align*} -\frac{8 \, C d^{3} - 6 \, B d^{2} e + 4 \, A d e^{2} + 2 \,{\left (4 \, C d^{2} e - 3 \, B d e^{2} + 2 \, A e^{3}\right )} x - 2 \,{\left (5 \, C d^{3} - 4 \, B d^{2} e + 2 \, A d e^{2} +{\left (5 \, C d^{2} e - 4 \, B d e^{2} + 2 \, A e^{3}\right )} x\right )} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) -{\left (C e^{2} x^{2} - 8 \, C d^{2} + 6 \, B d e - 4 \, A e^{2} -{\left (3 \, C d e - 2 \, B e^{2}\right )} x\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{2 \,{\left (e^{4} x + d e^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{- \left (- d + e x\right ) \left (d + e x\right )} \left (A + B x + C x^{2}\right )}{\left (d + e x\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \mathit{sage}_{0} x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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